Answers

2016-04-30T10:17:44+05:30
Let there be 1L. of this solution. 
Mass of solution : 1.19 * 1000 = 1190 g
Further, % of HCl in this solution :
                            =  \frac{38}{100} * 1190
                            = 452.2 g.
We know that : 
                           1 mole HCl       weighs         36.5 g
                           "x" moles HCl   weighs        452.2 g
moles of HCl = 452.2 g * \frac{1 mole  HCl}{36.5 g HCl}
                      = 12.389 moles 
  So, we have obtained that 12.39 moles of HCl are present in 1L of solution. Hence
                                Molarity (M) =  \frac{12.39 moles}{1L}
                                Molarity (M) = 12.39 moles/L
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