Answers

2016-04-30T16:37:42+05:30
3a(a+b+c)−2b(a−b+c)
3a
²+3ab+3ac-2ba+2b² -2bc
3a²+ab+3ac+2b²-2bc
4c(-a+b+c) = -4ac+4bc+4c²
(-4ac+4bc+4c²) - (3a²+ab+3ac+2b²-2bc)
-4ac+4bc+4c²-3a²-ab-3ac-2b²+2bc
(-4ac-3ac) - (4bc + 2bc) - 4c²- 3a² - ab - 2b²
-7ac + 6bc - 4c²- 3a² - ab - 2b²
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2016-04-30T19:56:57+05:30
Answer is -3a2+2b2+4c2-7ac-ab+2bc

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