Answers

2014-08-16T11:17:15+05:30
Let constant acceleration is a
distance travels in 20 seconds 
s = 0*20+a*20²/2
s = 200a -------------(1)
distance travels in first 10 seconds 
s1 = 0*10+a*10²/2
s1 = 50a -----------------(2)
distance travels in next 10 seconds 
s2 = s-s1
s2 = 200a-50a = 150a ----------------(3)
s2/s1 = 150a/50a = 3
0
2014-08-19T03:58:32+05:30

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Distance traveled in first 10 seconds
       S1 = u t + 1/2 a t²  = 0 t + 1/2 a 10² = 50 a

total distance traveled in 20 seconds =
     S = u t + 1/2 a t² = 0 t + 1/2 a 20² = 200 a

Distance traveled from 10s to 20s = S2 = 200 a - 50 a = 150 a


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