Comment has been deleted

Log in to add a comment

Comment has been deleted

Log in to add a comment

p(x) = 0

1. ax+b = 0

x = -b/a

2. ax = 0

as a ≠ 0 and for hole polynomial to be zero

x must be zero hence,

x = 0

p( -b/a)=a( -b/a)+b ax+b=0

= -b +b ax= -b

=0. therefore x=( -b/a)

Therefore,( -b/a)is the zero of the polynomial.

2.p(x)=ax

p(0/a)=a(0/a) ax=0

=0 therefore,x=(0/a)

Therefore (0/a) is the zero of the polynomial.