Answers

2014-08-16T21:04:55+05:30
MgCO3+CaCO3 ------------->MgO+CaO+2CO2
number of mole of CO2 = 2*number of mole of MgO
 no.of mole of CO2 = 2*4/40 = 1/5 mole
volume of 1 mole gas at stp = 22.4L
volume of CO2 = 22.4*1/5 = 4.48L
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