# Two bodies of masses m1 and m2 are communicated by a light inextensible string passing over a small smooth fixed pulley; m1 > m2. What is the acceleration of the system ? A. g (m1 + m2)/(m1 - m2) B. g (2m1 + m2)/(m1 - 2m2) C. g (m1 + 2m2)/(2m1 - m2) D. g (m1 - m2)/(m1 + m2)

1
by manojShah317

2014-08-17T17:43:52+05:30

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
It is the D .  m1- m2 /  m1 + m2

let T be the tension in the string and T is same in both sides of the string and on both sides it is directed upwards acting on m1 or m2.

we assume the string is not slipping over the pully.  no friction.

The equation of forces on the side of m1 is

m1 g - T  = m1 a      m1 moves down ward with acceleration a.

the equation of force s  on the side of m2 is
T - m2 g  = m2 a            m2 moves upwards with acceleration a