# Two equal sides of a triangle are each 5m less than twice the third side. If the perimeter of the triangle is 55m, find the lengths of its sides.

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Equal sides = a and b.

a = b = 2 c - 5

perimeter = a + b + c = 2c-5+ 2c - 5 + c =3c - 10

Hence 3c -10 = 55 meters

3c = 65 meters

c = 65/3 meters

a = b = 130/3 -5 = 115/3 meters

a = b = 2 c - 5

perimeter = a + b + c = 2c-5+ 2c - 5 + c =3c - 10

Hence 3c -10 = 55 meters

3c = 65 meters

c = 65/3 meters

a = b = 130/3 -5 = 115/3 meters