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Calculate the change in momentum of a car of mass 1000 kg when its speed increases from 36 km/h to 108 km/h uniformly?

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by sethuram812

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by sethuram812

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M = 1000 kg

v1 = 36 km/h = 10 m/s

v2 = 108 km/h = 30 m/s

p1 = 1000×10

= 10000 kg m/s

p2 = 1000×30

= 30000 kg m/s

Change = (30000-10000) kg m/s

20000 kg m/s

The change will be occur in Car direction where it was going before change.

v1 = 36 km/h = 10 m/s

v2 = 108 km/h = 30 m/s

p1 = 1000×10

= 10000 kg m/s

p2 = 1000×30

= 30000 kg m/s

Change = (30000-10000) kg m/s

20000 kg m/s

The change will be occur in Car direction where it was going before change.

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Change in momentum does not depend on whether the speed changes uniformly or not. We have to assume that the car is traveling in one direction only. Since speed is specified and not velocity. __Momentum is a vector. SO we find its magnitude and direction.__

V1 = 36kmph = 36*5/18 = 10 m/sec

V2 = 108 kmph = 30 m/sec

Change in momentum = final momentum - initial momentum

= p2 - p1 = m V2 - m V1 = m (V2 - V1)

**Magnitude of change in momentum = 1000 (30 -10) = 20,000 kg-m/sec**

**Change in momentum is +ve and it means that its direction is in the direction of motion of the car.**

V1 = 36kmph = 36*5/18 = 10 m/sec

V2 = 108 kmph = 30 m/sec

Change in momentum = final momentum - initial momentum

= p2 - p1 = m V2 - m V1 = m (V2 - V1)