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We see that given number is ending in 5 . so it is divisble by 5.

13915 / 5 = 2783

it is not even sumber, sum of digits is not divisble by 3, not divisible by 7. Observe that sum of alternate digits (even and odd digits) is same. So it is divisible by 11.

2783/11 = 253

again the sum off odd digits is same as even digits.

253/11 = 23 we know that 23 is a prime number

So 13915 = 5 * 11 * 11 * 23

13915 / 5 = 2783

it is not even sumber, sum of digits is not divisble by 3, not divisible by 7. Observe that sum of alternate digits (even and odd digits) is same. So it is divisible by 11.

2783/11 = 253

again the sum off odd digits is same as even digits.

253/11 = 23 we know that 23 is a prime number

So 13915 = 5 * 11 * 11 * 23

13915/5=2783

2783 HAS ALTERNATE DIGITS EQUALSO IT IS BY 11

2783/11=253

AS ALTERNATE DIGIGTS ARE AGAIN=SO BY 11

253/11=23

S0 5*11*11*23