# Hey guys, How to find the nth derivative of this equation:- y=x^2n

2
by Rohit03

2014-08-17T22:14:12+05:30

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It is simple and easy. differentiate once, second time. Observe the way sequence develops. Identify how to group factors.

See document enclosed for better answer

d/dx   X^2n  =  2n X^2n-1

d^2/dx^2  X^2n  =  2n  (2n-1) X^2n-2

d^3/dx^3  X^2n  =  2n  (2n-1) (2n -2) X^2n-3

d^n/dx^n  X^2n  =  2n  (2n-1) (2n-2) ....  [2n – (n -1) ] X^2n-n
=  P(2n , n)  X^n

2014-08-18T12:05:47+05:30

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