# 2 vectors of magnitude 9&7inclined at 60° calculate magnitude of resultant ?what angle is the resultant incline to vector of magnitude 9?

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by bhaja

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by bhaja

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P = 9 Q = 7 Ф = 60°

Resultant R is given by parallelogram law of forces

magnitude R² = P² + Q² + 2 PQ cos Ф = 81 + 49 + 2 7 * 9 cos 60°

R = √193 units

Angle made by R with P = 9 is given by

tan α = P sin Ф / [ P + Q cos Ф] = 9 sin 60° / [ 9 + 7 cos 60° ]

= 0.623

α = 31.945° angle made by Resultant with vector of magnitude 9

Resultant R is given by parallelogram law of forces

magnitude R² = P² + Q² + 2 PQ cos Ф = 81 + 49 + 2 7 * 9 cos 60°

R = √193 units

Angle made by R with P = 9 is given by

tan α = P sin Ф / [ P + Q cos Ф] = 9 sin 60° / [ 9 + 7 cos 60° ]

= 0.623

α = 31.945° angle made by Resultant with vector of magnitude 9