Answers

2014-08-18T21:35:29+05:30
The ans is 80 cm while sides are 30 , 16 and 34 
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2014-08-18T21:36:29+05:30
Let a right triangle ΔABC,in which angle B =90
AB = x cm, BC = y cm
a/q, 
       x-y = 14 ----------(1)
and, 
       Area =  \frac{1}{2}(BC)(AB)
120 =  \frac{1}{2} (x)(y)
2xy = 480     --------(2)
now, we know that , 
                   (x-y)^{2} =  x^{2} +  y^{2} -2xy
                     14^{2} =  x^{2} + y^{2} -480

                     x^{2} + y^{2} = 196+480 = 676   ----------(3)

            (x+y)^{2} =  x^{2} + y^{2} +2xy
               (x+y)^{2} = 676 + 480 = 1156
              x+y = √1156 = 34   ---------------(4)
From (1) & (4)
  2x = 48   therefore x= 24cm
from (1)
   y = x-14 = 24-14 = 10cm
therefore AB =24 cm,BC = 10cm
Ac =  \sqrt{ x^{2} + y^{2} }
AC =  \sqrt{ 24^{2}+ 10^{2}  } = \sqrt{676} = 26 cm
therefore perimetre = AB+AC +BC = 24+26+10 =60 cm 
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