# Area of a rectangle becomes double when the length is twice the breadth and area of the rectangle becomes half when length is reduced 4 times the breadth. then find the dimensions of the rectangle...........................?guys please say me the solution soon.................................................

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by miky
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2014-08-20T03:58:51+05:30

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Let A be area of rectangle with Length L and breadth B.
A = L B

2 A = 2B * B      =>   A = B²    or   B * B    ---- equation 1
As A = L B  => L = B    - equation 2

Area becomes half when Length is reduced 4 times breadth: means L is divided by 4B

A / 2  =   (L/4B) B  =>    A = L/2   -  equation 3

A  = L / 2 = B²  = L B = L²

B = 1/2   L = B = 1/2

dimensions of rectangle are  :  L = 1/2    B =  1/2    Area = 1/4

hey, do the dimensions work
if they don`t, then check where did you do boo-boo?
what does mean?
2014-08-20T13:50:44+05:30
Let area of rectangle be A
Length = x and breadth = y.
A = xy

Area becomes double when the length is twice the breadth

.......(1)

Since A = xy
⇒ x = y .......(2)

Area becomes half when Length is reduced 4 times breadth

......(3)

From equations

Since, x = y therefore,

So the dimensions are length = breadth =

That means, the given figure is a square.