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X² - x - 6 = 0

⇒x² - 3x + 2x - 6 = 0

⇒x(x - 3) + 2(x - 3) = 0

⇒ (x + 2)(x - 3) = 0

roots are -2 and 3

⇒x² - 3x + 2x - 6 = 0

⇒x(x - 3) + 2(x - 3) = 0

⇒ (x + 2)(x - 3) = 0

roots are -2 and 3

x²-3x+2x-6=0

x(x-3)+2(x-3)=0

(x+2)=0 (x-3)=0

x=-2 x=3

therefore -2 and 3 are zeroes of polynomial of x²-x-6