pls answer the question quickly

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The Brainliest Answer!

Method (1)

Method (2)

rule,

So, log(0.12) = log(12/100) = log(12) - log(100)

As, log(2) base_10 = 0.3010, log(3) base_10 = 0.4771, log(10) base_10 = 1

So, log(12) = 2 * 0.3010 + 0.4771 = 0.6020 + 0.4771 = 1.0791

And, log(100) = 2 * 1 = 2

So, log(0.12) = 1.0791 - 2 = -0.9209

Answer

0.7590

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N = log 0.2 / log 0.12 logarithms are with respect to base 10

log 0.2 = log 2 / 10 = log 2 - log 10 = log 2 - 1

log 0.12 = log 12/100 = log 3 * 2² /100 = log 3 + log 2² - log 100

= log 3 + 2 log 2 - 2

n = log 0.2 / log 0.12

= [ log 2 - 1 ] / [ log 3 + 2 log 2 - 2 ]

log 0.2 = log 2 / 10 = log 2 - log 10 = log 2 - 1

log 0.12 = log 12/100 = log 3 * 2² /100 = log 3 + log 2² - log 100

= log 3 + 2 log 2 - 2

n = log 0.2 / log 0.12

= [ log 2 - 1 ] / [ log 3 + 2 log 2 - 2 ]