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*The numbers divisible by 5 are { 5, 10, 15, ...180, 185, 190, 195 }*Let there be N5 = 39 numbers in this set. Apply the usual Arithmetic

progression formula for the sum.

Sum of these numbers S5: 39/2 [ 2*5 +38*5] = 3900

*Numbers divisible by 3 are { 3, 6, 9, 12, 15, ..... 180, ..., 195, 198 }*Let there be N3 = 66 numbers in this set.

Sum : S3 = 66/2 [2*3+65*3] = 6633

*Numbers divis*

*ible by both are : { 15, 30, .... 180, 195 } .*let there be N15 = 13 numbers in this set.

These numbers are present in both sets. they will be counted & added twice.

Sum : S15 = 13/2 [ 2*15+12*15] = 1365

*Sum of the Numbers which we want are = S5 + S3 - S15 =*

*= 3900 + 6633 - 1365*

**= 9168**