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Pb(NO3)2 + KI -----> KNO3 + PbI2
white precipitate of LEAD [II] IODIDE is formed

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Lead (II)  so
Pb (NO3)2  (in aqua )  + 2  K I (in aqua) ---->  2  K NO3  +  Pb I2

 Pb (NO3)_{2}  (aqua) + 2 K I (aqua)  => 2 K NO3 + Pb I_{2}  (Solute)

The lead iodide thus formed is yellow. it is not soluble in cold water. But in hot water it is soluble.

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