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## Answers

The Derivative of THE natural log ln(x) which is log(base)e or e^x is:

dy/dx of e^x = e^x

dy/dx of e^f(x) = f '(x)e^f(x)

dy/dx of lnx = 1/x

dy/dx of [ln[f(x)] = f '(x)/f(x)

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The Derivative of THE natural log ln(x) which is log(base)e or e^x is:

dy/dx of e^x = e^x

dy/dx of e^f(x) = f '(x)e^f(x)

dy/dx of lnx = 1/x

dy/dx of [ln[f(x)] = f '(x)/f(x)