# At a given temperature the pressure of a gas reduces to 75% of its initial value and the volume increases by 40% of its initial value. Find this temperature if the initial temperature was -10degreeC.

1
by Chottu1501

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by Chottu1501

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let P1 = P and V1 = V

P2 = 3P/4

V2 = V + V*40/100

V2 = 7V/5

T1 = 273-10 = 263K

T2 = ?

P*V/263 = (3P/4)(7V/5)/T2

T2 = 21*263/20

T2 = 276.15

t2 = 276.15-273 = 3.15degreeC