Answers

2014-03-01T21:07:07+05:30
4x^2 - 2(a^2 + b^2)x + a^2b^2 = 0

=>
4x^2 - 2a^2x - 2b^2x + a^2b^2 = 0

=>2x(2x - a^2) - b^2(2x+a^2)

=>(2x+a^2)(2x-b^2)

so value of x are -(a^2/2) and (b^2/2)
4 2 4