The horizontal range and maximum height attained by a projectile are R and H respectively. If a constant horizontal acceleration a = g ÷ 4 is imparted to the projectile due to wind in the direction of motion then its horizontal range and maximum height will be?Answer should come (R + H), H

1
by Deleted account

2014-08-24T02:19:37+05:30

This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Normal projectile motion , with no acceleration in horizontal direction.

H =  u² sin² Ф / 2g                u = initial speed, Ф angle of projection

R =  u² sin 2Ф / g

With a constant acceleration due to wind in horizontal direction:

Time of flight remains same and is dependent on vertical component of velocity.

H"  = same as H = u² sin² Ф / 2 g                as there is no modification in y direction

R"  = [u² sin 2Ф / g ] +  1/2 (g/4)  (2 u sin Ф÷g)²  , as    acc = g÷4     t= 2 u sinФ÷g

= u² sin 2Ф / g + 1/2 u² sin² Ф / g

= R + H