Yes.

done))))

Thankyou so much! :)

But to not Pythagorus theorem right? It's distance formula. :)

No it is Pythagorus distance formula

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Yes.

done))))

Thankyou so much! :)

But to not Pythagorus theorem right? It's distance formula. :)

No it is Pythagorus distance formula

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Use Pythagoras:

The two expressions are equal, so

The point is

ab=ac

root of (-2-0)sq + (s-y)sq=root of (2-0)sq + (-3-y)sq

4+25+Ysq - 20y=4+9+Ysq+6y

25-10y=6y+9

therefore y=1

co-ordinate point on y-axis is (0,1)