# Aflight is flying at a height of 10400m and with a speedof 885km/hr. A person jumps out of it to the sea down below. How long will he take to reach the surface of water?

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by jamunajohn88

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by jamunajohn88

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10400m

using

10400 = 1/2 x 10 x t²

t= √(2080)

10400 = 1/2 x 9.8 x t²

t = 46.046 seconds

using

10400 = 1/2 x 10 x t²

t= √(2080)

10400 = 1/2 x 9.8 x t²

t = 46.046 seconds

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

The time duration to reach the surface of water is dependent on the height above water surface and not on the speed of the flight.

S = 1/g t² => 10,400 = 1/2 *9.81 * t²

t = 46.046 seconds

S = 1/g t² => 10,400 = 1/2 *9.81 * t²

t = 46.046 seconds