ABC is a right triangle right angled at B. BD is perpendicular bisector of AC. Find ratio of ar(DBC) and ar(abc). Relate this answer to triangles chapter

2
by saketsorcerer

2014-08-27T05:56:16+05:30

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Let us take the two triangles  ΔBDA and ΔBDC. These two are congruent as:

DA = DC (as BD is bisecting AC), DB is common, and the
Angle BDA = angle BDC = 90  (BD perpendicular to AC)

So It is easy now that:  angle DBA = angle DBC

Since their sum is the angle ABC = 90 deg (given),

Hence      angle DBC  = 1/2 angle ABC. = 45 deg.

Ratio = 1/2

It would be good to show images for these kind of answers. It will make the student understand better.
thanks for suggestion. do u make diagrams ? have u seen how many i make.. no offence . it is a point i am clarifying
I generally give a solution to a geometry question with a diagram only ...otherwise how can a child understands?
It would be always good to give an answer with a diagram...in brainly ...you have an option to upload an image which supports your solution....that will make the child understand your solution better
2014-08-27T19:04:21+05:30
Area of triangle ABC =

Area of triangle BDC =

Area of triangle BDC =

Area of triangle BDC =

So,

The ratio of areas of triangles BDC and ABC is equal to 1 : 2