Answers

2014-08-27T22:44:19+05:30
2014-08-27T22:50:49+05:30
In ΔPQR,
                Q = 25 , R =65
we know that, 
      P+Q+R =180
or,  P+25+65=180
 or, p = 180-90
or,  P = 90
therefore, in ΔPQR,
                         hypotaneus = QR
                         perpendicular =RP
                          base = PQ
Now, from Pythagourous theorem, 
                \\  PQ^{2} + RP^{2} = QR^{2}
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