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2014-08-29T13:46:09+05:30

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The heat supplied by steam = latent heat + heat due to higher temperature at 100 deg.

 Let\ the\ mass\ of\ steam\ =\ m\ grams \\ \\ s\ =\ specific\ heat\ =\ 1\ cal/gram/deg C\ =\ 4.184 Joules/gram/deg C \\ \\ Heat\ lost\ by\ steam\ =\ Heat\ gained\ by\ cold\ water \\ \\ m\ grams\ *\ 2.26\ kJoules/gm +\ m\ 4.184 (100 - 25) deg\ C\ =\ 100\ gram \ *\ 4.184\ *\ 5\ deg\ C \\ \\ m\ *\ 2.26\ +\ 4.184\ *\ 75\ m\ =\ 100\ *\ 4.184\ *\ 5 \\ \\ m\ =\ 6.619\ grams\ of\ steam \\ \\

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wheres the answer
bt specific heat of water is 4.2 write
4.2 and 4.184 nearly same - this is from a manual i have taken. if u want to use 4.2 please do that.