Answers

  • Brainly User
2014-08-31T19:12:32+05:30
As  a+b=2rootab
squaring bth side..  (a+b)^2=4ab
expanding terms,  a^2+b^2+2ab-4ab=0
or  (a-b)^2=0
hence  a=b
so a/b=1
1 4 1
2014-08-31T19:42:03+05:30
 \frac{a+b}{ \sqrt{ab} } = \frac{2}{1}
or,  \frac{a}{ \sqrt{ab} } + \frac{b}{ \sqrt{ab} } =2
or,  \sqrt{ \frac{a}{b} } +  \sqrt{ \frac{b}{a} } =2
LET, X =  \sqrt{ \frac{a}{b} } ,then,  \frac{1}{X} =  \sqrt{ \frac{b}{a} }
now,  X+ \frac{1}{X} =2
or,  X^{2} -2x+1=0
or, ( X-1)^{2} =0
therefore X = 1
so,  \sqrt{ \frac{a}{b} } =1
or, a/b =1
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