Answers

2014-09-01T13:50:35+05:30
We know that.
F=Gm₁m₂/d²
⇒20=6.67*10⁻¹¹*20*m₂/25
⇒25=6.67*10⁻¹¹*m₂
⇒m₂=3.74*10¹¹kg
1 5 1
2014-09-01T16:34:59+05:30
Let m=m1=?
m2=20kg
Distance, r = 5m
F=20N
From the relation, F=G \frac{m1*m2}{r^2} , Where\ G=6.67*10^{-11} Nm^2kg^{-2}
Substituting the values of G, m2, F & r, we get
20=6.67*10^{-11} * \frac{20* m_{1}}{(5)^2}
Rearranging the equation we get:- 
 \frac{20*25}{20*6.67*10^{-11}} = m_{1}
Solve, we get:-
m_1=3.748*10^{11} kg


0