Two water taps together can fill a tank in 75/8 hours. The tap of larger diameter takes 10hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.

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let the time taken by smaller tap be x and time taken by larger tap is x+10. as per sum the equqtion will be 1/x+1/x+10is8/75. if u solve this quqdratic equqtion u may get your required answer. answer is larger tap 15hrs and smaller tap 25hrs.

Answers

2014-03-02T21:37:39+05:30
Say the smaller tap fill the tank in x hours
and the bigger tap fill the tank in (x-10) hours

Therefore in 1 hour the small tap can fill 1/x part of the tank.
and, in 1 hour the small tap can fill 1/(x-10) part of the tank.

Two water taps together can fill a tank in  75/8 hours

So,, in one hour the taps fill 8/75 portion of the tank. so the equation will be,

1/(x) + 1/(x-10) = 8/75
=>4x^2 - 115x + 375 = 0 (solving eventually)
=>(4x-15)(x-25)

so, solving the equation we will get X = 15/4 and 25

so, if, x =15/4  than (x-10)= -25/4 (it is not possible because time cant be negative)

If x=25 than (x-10) = 15

thus, the smaller tap fills the tank in 25 hours where the large tap fills it in 15 hours.
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2014-03-02T22:33:59+05:30
 the smaller tap fills the tank in 25 hours and the large tap fills it in 15 hours.
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