# Explain electric field in a conductor when the circuit is closed.

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by ramya10class

2014-09-02T21:12:28+05:30

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Force between two electric charges is by coulomb's law = F = (1/4π∈ ) q1 *q2 / d²

Electric field at point P2 due to charge at P1 is F/q2  = (1/4π∈) q2 / d²

Electric field exists at a point P2 when there is a potential difference between two points P and Q and P2 is in between them.

When a conductor is connected in a circuit and a battery is connected, there is a potential difference V volts created between the ends of the battery terminals. As the ends of the conductor are connected to the battery terminals, the potential difference creates an electric field = E = V / L, where L is the length of the conductor. There are a lot of positive charge at positive terminal and negative charge at anode in the battery. When circuit is on the electrons move from anode to cathode.

The electric field is uniform along the length of conductor if it is uniform along the length. The field is directed from the positive terminal ( higher potential point) to negative terminal.

The electric field acts on electrons (-minus charge) and so they are forced to move towards the positive terminal.