Answers

2014-09-04T08:30:02+05:30
 \frac{sin^3A+cos^3A}{sinAcosA} +sinAcosA
  \\  \frac{(sinA+cosA)(sin^2A+cos^2A-sinAcosA)}{sinAcosA}+sinAcosA \\ sin^2A+cos^2A-sinAcosA+sinAcosA
 \\ =1
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this is not the question. it is an error
2014-09-04T16:13:07+05:30
Given that  \frac{Sin^3A + Cos^3A}{SinA+CosA+SinACosA}

But it should be  \frac{Sin^3A + Cos^3A}{SinA+CosA-SinACosA} 

We know that,

(a+b)^3 = (a+b)(a^2+b^2-ab)

 \frac{(SinA+CosA)(Cos^2A+Sin^2A - CosASinA)}{(Cos^2A+Sin^2A - CosASinA)}

SinA + CosA


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