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2014-09-04T03:13:13+05:30

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As we can see the first term is 1, second term is 2 and  so on.

It is an arithmetic progression with a common difference 1 and starting term 1.

a = 1  d = 1

Tn = n    OR,  a + (n-1) d = 1 + (n-1)1 = n

Sum of n terms =  n (n+1) / 2


1 5 1
2014-09-04T13:41:21+05:30
This is an AP
a = 1 and the common difference, d = 1
nth term:
t_n = a + (n-1)d
t_n = 1 + (n-1)1
t_n = 1 + n-1
t_n = n
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