Answers

2014-03-03T11:21:32+05:30
Perimeter is 68cm
we know that diagonals of a rhombus bisect each other at 90 degrees
so acc. to Pythagoras theorm
AC^2  = AB^2 + BC^2  
         = 64 + 225
         = 289
AC = 17cm
So perimeter = 17*4
                    =   68cm

0
2014-03-03T11:54:26+05:30
The diagnols of a rhombus bisect each other and are perpendicular to each other therefore side of rhombus=root of (15^2+8^2)=root of (289)= 17 therefore perimeter of square=68
0