There are 5 different routes to travel between city A and city B.If the routes are chosen at random, in how many ways one can go from city A and city B and come back to city A? What is the probability that the same route is not taken while returning?



One can go 5*5 = 25 different ways and the probability that one doesn't take the same route back is 4/5
There are 5 different routes, so the number of ways you can come and return back will = 25 (5×5 routes) If the same route cannot be taken while coming back without 1 route =24
Sorry, the 2nd part of the answer is 4/5×25= 20 but my phone is not allowing me to change it.... Mordeator's please don't delete