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3x + 2y = 90 -(1)

cos (3x-2y)=√3/2 (using trignometric table we get cos30=√3/2)

3x - 2y = 30 -(2)

Adding equation 1 and equation 2, we get

(3x + 2y) + (3x - 2y) = 90 +30

3x + 3x + 2y - 2y =120

6x = 120

x= 20

Now putting the value of x in equation 1, we get

3(20) + 2y =90

60 + 2y =90

2y = 90 - 60

2y = 30

y = 15