# The ages of Leena and Heena are in the ratio 7:5 . Ten years hence, the ratio of their ages will be 9 : 7. Find their present ages.

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by Manesika

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by Manesika

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ten yrs hence therir ages as 9 : 7

therefore (9x + 10) / 7x+10 = 7/5

cross multiply we get

45x + 50 = 49x + 70

49x - 45x = 70 - 50

4x = 20

x = 5

their present ages 9x+ 10 = 9 (5) + 10 = 55

7x+ 10 = 7(5) + 10 = 45

their ages are 55,45

The Brainliest Answer!

ten Years later(hence) the ratio of their ages is 9 :7

(9x + 10) / 7x+10 = 7/5

45x + 50 = 49x + 70 [by cross multiplying each other]

49x - 45x = 70 - 50

4x = 20

x = 5

Hence present age of Leena = 7x=7*5= 35 years.

Present age of Heena=5x=5*5=25 years