yes

from (a-x) to (z-x)

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its so easy you just need to know the logic

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yes

from (a-x) to (z-x)

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its so easy you just need to know the logic

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(a-x)(b-x)(c-x)...........(x-x)(x-y)(x-z)

=(a-x)(b-x)(c-x)....(0)(x-y((x-z)

=0

the value of x-x is 0

any thing multiplied by 0 is 0

hence (a-x)(b-x)(c-x)....(y-x)(z-x)=0