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## Answers

'When a+ b+ c = 0 , a³ + b³ + c³ = 3abc '

Here, a = p-q , b = q-r , c= r-p

And, a+b+c= p-q +q-r +r-p = 0.

So, (p-q)³ + (q-r)³ + (r-p)³ =

**3(p-q)(q-r)(r-p)**

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'When a+ b+ c = 0 , a³ + b³ + c³ = 3abc '

Here, a = p-q , b = q-r , c= r-p

And, a+b+c= p-q +q-r +r-p = 0.

So, (p-q)³ + (q-r)³ + (r-p)³ =