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## Answers

a³+b³+c³ - 3abc = (a+b+c)(a²+b²+c² -ab - bc - ca)

Here a = x, b = (-3)y, c = (-4)z

So given expression is factorised as:

[x +(-3y)+(-4z)][x² + (-3y)² + (-4z)² - x(-3y) - (-3y)(-4z) - (-4z)x

Please complete yourself . It will give you a little practice.