Find The Number Of Zeros in 1^1*2^2*3^3*4^4 …. 48^48*49^49 ?

2
explain
sorry ans is 10 to power 225
10^10*10^20*10^30
10^10*10^20*10^30*10^40*10^5*10^15*10^25*10^35*10^45
i got ans but need explanation...total zeros at the end of product 5^5 x 10^10 x 15^15 x 20^20 x 25^25 x 30^30 x 35^35 x 40^40 x 45^45 will be 5+10+15+20+50+30+35+40+45 = 250 zeros

Answers

2014-03-05T10:19:03+05:30
10^10 * 20^20 *30^30 * 40^40 = so the number of zero is 10^{144}


1 5 1
yes but 5 is the one which brings a zero (5+5)
how five is 1??
just look........1^1 x 2^2 x 3^3 x 4^4 x 5^5 so on so far. now 5^5 in the first digit systen which can brings a zero. (5^5 x 10^10) = 13 zeros.
how in this 5^5 contributes 5 5's
your ans. is wrong here 5^5*4^4 will give something * 10^5 similarly 15^15*16^16 will give something *10^15...............
2014-03-05T11:17:10+05:30
Answer is 1 as anything raise to power 1 is 1

0
1^1 is 1 is correct but the full sum Find the number of zeros in 1^1* 2^2*3^3...49^49*50^50