# The perimeter of a rectangular garden , whose length is 4m more than its width is 40m. find the dimensions of the rectangle

2
by karthik2000

Log in to add a comment

by karthik2000

Log in to add a comment

then length(l) = (x+4) m.

a/q,

perimeter of rectangle = 40 m.

or, 2(l+b) = 40

or, 2(x+4+x) = 40

or, 2(2x+4) =40

or, 4x+8 =40

or, 4x = 40-8

or, x = 32/4

x= 8

so, width(b) = x = 8 m.

And, length(l) = x +4 = 12 m

therefore its dimension is 12m×8m

given that the length is 4m more than its width

so the length of the rectangle be x+4

And perimeter=40m

perimeter of a rectangle is

p=2(l+b)

Replacing p=40,l=x+4 and b=x

we get

40=2(x+4+x)

40=2(2x+4)

dividing both sides by 2

20=2x+4

adding -4 on both sides

2x+4-4=20-4

2x=16

dividing both isdes by 2

2x/2=16/2

x=8

Thus the width of the rectangle be 8m

and the length of the rectangle be

x+4=8+4=12m

length of the rectangle be 12m