Answers

2014-09-17T16:13:38+05:30
Zeroes are 1 and 4
(x-1)(x-4)are factors
x^2-5x+4 is a factor
on dividing,
we get quotient=x^2-3
=(x- \sqrt{3})(x+ \sqrt{3})
hence,√3 and -√3 are remaining zeroes
0
2014-09-17T16:42:11+05:30
ATQ zeros are 1 and 4 therefore(x-1) and (x-4) are factor therefore x^2-5x+4 is a factor on dividing we quotient=x^2-3=(x-√3)(x+√3)
0