# If sum of lcm and hcf of two no is 7380.if lcm of these no is 7340 more than their hcf ,find the product of two no

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Let, HCF be x

LCM will be x+7340

therefore, x + (x + 7340) = 7380

2x = 7380-7340

2x = 40

x = 40/2

x= 20

hence, HCF = 20

LCM = (x+7340) = 20+7340 = 7360

at last, 20 X 7360 = 147200

L.C.M. x H.C.F. = product of those two no.s

let L.C.M. x and H.C.F be y

x+y=7380-----------------------(1)

x=y+7340-----------------------(2)

BY SUBSTITUTION

(y+7340)+y=7380

2y=40

y=20

x=y+7340

x=7360

product of mubers= product of their H.C.F and L.C.M

=20x7360

= 147200