# IN THE FIGURE IN ATTACHMENT, DB AND AC PERPENDICULAR TO BC AND DE PERPENDICULAR TO AB. PROVE ΔBDE SIMILAR TO ΔABC

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The Brainliest Answer!

angle DBE in triangle DBE = angle BAC in triangle ABC as these are alternate angles ----------------(1)

angle DEB i triangle DBE = angle ACB in triangle ABC (both 90) ---(2)

Therefore all the angles of triangles BDE and ABC are equal.

Hence these triangles are similar.

Angle BAC= Angle DBE ,[ BD is parallel to AC ,(alternative angle) ]

Angle ABC = Angle BED = 90 ,(Given)

if two angles of two tringle are equal corresponding then those third angle are also be equal .

so, Angle ABC = Angle BDE

therefore ΔABC is similar to ΔBDE [ By AAA similarity]