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If a + b + c = 12, then a² + b² + c² = 90, then find the value of a³ + b³ + c³ - 3abc.

SUPER URGENT!!!!! PLEASE!!!!!

1
by Yasmin

is tis crrct?

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SUPER URGENT!!!!! PLEASE!!!!!

by Yasmin

is tis crrct?

Log in to add a comment

Given a+b+c=12,a²+b²+c²=90

(a+b+c)²=(a²+b²+c²)+2(ab+bc+ac)

12²=90+2×(ab+bc+ac)

54=2(ab+bc+ac)

(ab+bc+ac)=54/2=27

a³+b³+c³-3abc=12×90-(27)

=12×63

=756