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## Answers

5x+4y=30

5x=30-4y

x=

__30-4y__

5-------------------------1

Putting the value of x in equation 2.

3(30-4y/5)+y=11

90-12y+5y=55 [By taking L.C.M]

-7y=55-90

-7y=-35

y=-35/-7

y=5

putting the value of y in 1.

x=30-4(5)/5

x=30-20/5

x=10/5

x=2

3x+y=11-------(2)

now multiplying equation (2) by -4

-12x-4y=-44-----(3)

to eliminate y add (1) and third equations

5x-12x+4y-4y=-44+30

-7x=-14

dividing both sides by -7

x=2

substituting x=2 in equation (2)

3x+y=11

3(2)+y=11

6+y=11

adding -6 on both sides

-6+6y=11-6

y=5

thus the values are x=2 and y=5