Answers

2014-09-22T15:03:51+05:30
2Na⁺  +   2e⁻   =  2Na
2Cl⁻   +   2e⁻   =  2Cl
the overall reaction is that
2Na⁺Cl⁻  =  2Na⁺  +   Cl₂⁻
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sodium ions on cathod rod and chlorine on anode rod