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## Answers

4y²+16y-3y-12=0

take 4 as common in first two terms and -3 as common in next two terms

4y(y+4)-3(y+4)

take y+4 as common

(4y-3)(y+4)=0

by using the principle of zero products

4y-3=0 or y+4=0

4y=3 or y=-4

y=3/4 or y=-4

thus the values of x are 3/4 and -4

The factors are (4y-3)(y+4)

(4y-3)(y+4) = 0

4y-3=0⇒4y=3⇒y=3/4

y+4=0⇒y=-4

the values of y are 3/4 and -4