Answers

2014-09-24T22:36:23+05:30
Let the numbers be x, 2x and 3x
a/q
xx^{3} + 8x^{3} + 27x^{3}   = 98784

or 
36 x^{3} = 98784
or 
 x^{3} = 98784/36
or 
 x^{3} = 2744
or
x =  \sqrt[3]{2744}
or
x = 14

2x= 28
3x= 42
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2014-09-24T22:46:50+05:30
The numbers be y 2y 3y
because their ratio is 1;2;3
given that sum of their cubes is 98784
therefore (Y)^3 +(2y)^3 +(3y)^3= 98784
(y)^3+8(y)^3+27(y)^3=98784
36(y)^3=98784
(y)^3 = 98784/36=2744
y=cube root(2744)
y=14
therefore the numbers are 14 28 42
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