please give me answers quick exam is comming soon

Log in to add a comment

please give me answers quick exam is comming soon

Log in to add a comment

we know that diagonals of rhombus are perpendicular to each other .

now in ΔABC,BO IS PERPENDICULAR to AC

THEREFORE AREA of ΔABC =×BO×AC

similarly in ΔADC

area of ΔADC=×DO×AC

AREA OF RHOMBUS=area of ΔABC+area of ΔADC

=×BO×AC+×DO×AC

=×AC[BO+DO]

=×AC×BD